If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2+12x=6
We move all terms to the left:
8x^2+12x-(6)=0
a = 8; b = 12; c = -6;
Δ = b2-4ac
Δ = 122-4·8·(-6)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{21}}{2*8}=\frac{-12-4\sqrt{21}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{21}}{2*8}=\frac{-12+4\sqrt{21}}{16} $
| 1/2x+3+6=10 | | 3x/2+5/3=-x/6-1 | | -2t+5=-3t+11 | | 3u-78=u+10= | | 6x+4=-x+1 | | -3/4x+3+5/4x+6=10 | | 9(p−4)=−18 | | 3(x-1.8=)2x+1 | | 6(3+7p)=8(3p+9) | | 72=4d+8 | | (m+2)/3=-1 | | 6x-3=37-2x | | 4(8j-7)=100 | | 48=6r-5 | | 3x^2-18x+13=0 | | 5x-3=2+3x/2 | | 3w-8=w+22 | | 5r-r=0 | | 8=7x^2+3x | | 6−y=15 | | (17x+13)+(32-2x)=90 | | 5k+3k=8 | | 3x^2+15=5 | | 30.16=17.56=5x | | 6x+9=-6x+11 | | F(x)=5x+100 | | 3x-4=4x+16 | | 5r^2-33r+150=) | | 3x+30=11-58 | | 9/4=x/5.3 | | 2x+28=10x | | 3*4v=12v |